The path difference between two interference | vedclass

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(A) For constructive interference (bright fringe),the path difference must be an integral multiple of wavelength,i.e.,$\Delta x = n\lambda$,where $n =

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(A) For constructive interference (bright fringe),the path difference must be an integral multiple of wavelength,i.e.,$\Delta x = n\lambda$,where $n = 0, 1, 2, \dots$.For destructive interference (dark fringe),the path difference must be an odd multiple of half-wavelength,i.e.,$\Delta x = (2n + 1) \frac{\lambda}{2} = (n + 0.5) \lambda$,where $n = 0, 1, 2, \dots$.Given path difference $\Delta x = 11.5 \lambda$.Comparing this with the condition for destructive interference: $11.5 \lambda = (n + 0.5) \lambda \implies n + 0.5 = 11.5 \implies n = 11$.Since $n$ is an integer,the condition for a dark fringe is satisfied.

The path difference between two interference waves at a point on a screen is $11.5 \lambda$. The point is

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